Question

D is a point on the side BC of a ΔABC such that AD bisects ∠BAC. Then
a) BD : DC = AB : AC
b) CD > CA
c) BD > BA
d) BA > BD
please give the answer with explanation
if you give the wrong answer or without the correct explanation I Will Report You

Answer 1

Question :-

D is a point on the side of a ∆ABC such that AD bisects ∠BAC . Then

a)BD:DC = AB:AC

b)CD>CA

C)BD>BA

d)BA>BD

explanation:-

Look at the diagram you Should must be Understand.

Solution:-

{In triangle ABC}

= Let ABD = ∠4

=. ADC= ∠3

=. BAD=∠1

=. CAD =∠2

now,

∠4 =∠2+∠C. (exterior Angle of a Triangle)

☛∠4 > ∠2

But

∠1 = ∠2 (AD is angle bisector )

So,

∠4 > ∠1

= BA = BD (Side opposite to greater Angle is Longer).

Hence, Verified ✍️

Please mark me Brainlist:)

Answer 2

Answer:

Question :-

D is a point on the side of a ∆ABC such that AD bisects ∠BAC . Then

a)BD:DC = AB:AC

b)CD>CA

C)BD>BA

d)BA>BD

explanation:-

Look at the diagram you Should must be Understand.

Solution:-

{In triangle ABC}

= Let ABD = ∠4

=. ADC= ∠3

=. BAD=∠1

=. CAD =∠2

now,

∠4 =∠2+∠C. (exterior Angle of a Triangle)

☛∠4 > ∠2

But

∠1 = ∠2 (AD is angle bisector )

So,

∠4 > ∠1

= BA = BD (Side opposite to greater Angle is Longer).

Hence, Verified ✍️