D is a point on the side BC OF A TRAINGLE AB C SUCH THAT AD BISECTS ANGLE BCA THEN
a) BD = CD
b) BA > BD
c) BD > BA
d) CD > CA
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Step-by-step explanation:
We are given that D is a point on the side BC of a triangle ABC such that AD bisects angle BAC. And we have to show that BA > BD. Now, as we know that the exterior angle of a triangle is greater than the interior opposite angles of the triangle. Hence proved that BA > BD.
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