Question

D is a point on the side BC of a triangle ABC such that TRIANGLE ABC TRIANGLE BAC show that CA^2=BC×CD

Answer 1

IN ΔABC AND ΔADC
∠C = ∠C (COMMON)
∠BAC =∠ADC
∴ ΔABC ≈ ΔADC    (AA CRITERIA)
∴AC/DC = BC/AC      (CPST)
∴CA²=CB*CD

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Answer 2

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