Question

D is a point on the side BC of a triangle ABC such that AD bisects angle BAC. Then
a) BD:DC = AB:AC
b) CD>CA
c) BD>BA
d) BA>BD

Please solve the above mentioned questions. ​

Answer 1

Answer:

(d) BA>BD

Step-by-step explanation:

mark me as a brainlist

Answer 2

Option D ( BA > BD) is correct.

Step-by-step explanation:

⇒ Given, ΔABC such that AD bisects ∠BAC

⇒ As AD bisects ∠BAC hence,

∠BAD = ∠CAD

⇒ In ΔACD, ∠ADB is exterior angle.

⇒ Hence, ∠ADB > ∠DAC

(∵ exterior angle is greater than interior angle)

⇒∠ADB > ∠BAD (∵ ∠BAD = ∠CAD)

⇒ BA > BD (side opposite to greater angle is greater)

Hence, option D is correct.