D is any point on side ac of a triangle abc with ab=ac.Show that cd bd
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In any Triangle, any single side is always less than the sum of other 2 sides. If this is not the case then we won’t have a Triangle.
Applying this logic, we know that ab + bc > ac (All these are lengths)
But ac is same as ad+dc (d is a point on ac, as given).
Therefore ab + bc > ad + dc, which is same as
ab + bc > ab + dc (since ad is same as ab, as given)
Subtracting ab from both sides, we get ab + bc - ab > ab + dc -ab
Cancelling ab on both sides, we get
bc > dc
Hence proved.
Hope it helps you
Applying this logic, we know that ab + bc > ac (All these are lengths)
But ac is same as ad+dc (d is a point on ac, as given).
Therefore ab + bc > ad + dc, which is same as
ab + bc > ab + dc (since ad is same as ab, as given)
Subtracting ab from both sides, we get ab + bc - ab > ab + dc -ab
Cancelling ab on both sides, we get
bc > dc
Hence proved.
Hope it helps you
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