D is any point on side AC of triangle ABC with AB = AC. Show that CD<BD.
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Since, AB = AC, angABC = angACB. - 1) Now, angABC = angABD + angDBC => angDBC = angABC - angABD => angDBC < angABC => angDBC < ang ACB {using 1))} => DC < BD ( side corresponding to larger angle is larger than side corresponding to smaller angle)
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Since, AB = AC, angABC = angACB. - 1)
Now, angABC = angABD + angDBC => angDBC = angABC - angABD => angDBC < angABC => angDBC < ang ACB {using 1))} => DC < BD ( side corresponding to larger angle is larger than side corresponding to smaller angle)
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