D is mid point of side BC. if angle B= angle C , prove that AD bisects angle A
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It is given that
angle b = angle c
d is the mid point
Therefore in triangle ABD and triangle ACD
bd=dc (given)
<b= < c ( given)
ad = ad ( common )
triangle ABD congruent to triangle ACD (ASA CRITERIA)
Angle BAD = Angle CAD
Therefore AD bisects angle A
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Note: This type of question is solved in a very limited method. The above method is a very good method to solve such questions in which there will be less chances of doubt and errors. Here we have used the area formula for triangles based on Heron’s method.
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