D is mid point of side BC of a triangle ABC and E is mid point of BD.If O is mid point of AE , then prove that ar(BOE)=1/8ar(ABC)
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ar(ABD)=ar(ADC) [Triangle on the same base and on between same parallel lines]...(1)
ar(ABE)=ar(AED) [Triangle on the same base and on between same parallel lines] ....2
ar(BOE)=ar(BOA) [Triangle on the same base and on between same parallel lines] ....3 now
2 ar(ABD)=ar(ABC) from1
4ar(ABE)=ar(ABC) from2
8ar(BOE)=ar(ABC) from3 So;ar(BOE)=1/8ar(ABC) proved
ar(ABE)=ar(AED) [Triangle on the same base and on between same parallel lines] ....2
ar(BOE)=ar(BOA) [Triangle on the same base and on between same parallel lines] ....3 now
2 ar(ABD)=ar(ABC) from1
4ar(ABE)=ar(ABC) from2
8ar(BOE)=ar(ABC) from3 So;ar(BOE)=1/8ar(ABC) proved
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