Question

D is the mid point of AC, if DF =DE prove that triangle ABC is iaosceles​

Answer 1

Answer:

In triangles BED and CFD ,

BD= DC ( Dis the midpoint)

DE = DF ( given)

Angles BED and CFD are both right angles.

Hence the triangles are congurent by RHS condition.

Thus angles B and C are equal by c.p.c.t

thus AB = AC ( sides oppposite to equal angles of a triangle are equal).

Step-by-step explanation:

Answer 2

Given: D is the mid-point

Thus AD=DC

DF=DE

To Prove:ABC is an isossceles triangle ie AB=AC

Proof

As DF=DE

Therefore, angleABC= angleACB

Thus,AB=AC(sides opposite to equal angel are equal)

So,ABC is an issosceles triangle

Hence proved

Hope it helps!