D is the mid point of BC ansd perpendicular DF and DE to sides AB and AC respectively are equal in length. prove that triangle ABC is an isosceles triangle .
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If ABC is a triangle and D is a midpoint of BC, and the perpendiculars from D to AB and AC are equal, how do you prove that the triangle is isosceles?

In triangles BED and CFD ,
BD= DC ( Dis the midpoint)
DE = DF ( given)
Angles BED and CFD are both right angles.
Hence the triangles are congurent by RHS condition.
Thus angles B and C are equal by c.p.c.t
thus AB = AC ( sides oppposite to equal angles of a triangle are equal).


In triangles BED and CFD ,
BD= DC ( Dis the midpoint)
DE = DF ( given)
Angles BED and CFD are both right angles.
Hence the triangles are congurent by RHS condition.
Thus angles B and C are equal by c.p.c.t
thus AB = AC ( sides oppposite to equal angles of a triangle are equal).

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