D is the midpoint of BC side BC of a triangle ABC ad is the bisector a and b is produced cuts AC at the point x prove that b is to the power x is equal to 3 raise to power one
Answers
Answer:
3:1
Step-by-step explanation:
Let's take point Y on seg AC such that DY | | BX.
As D is a midpoint of BC, by converse of midpoint theorem, XY=YC.
Applying midpoint theorem in triangle CDY, BX=2DY.
As E is a midpoint of AD & EX | | DY,
AX=XY.
Applying midpoint theorem in triangle DAY, EX= DY/2
BE/EX = BX-EX / EX
= 2DY - DY/2 / DY/2
= 3DY / 2 * 2/YD
= 3DY/DY
= 3:1.
Answer:
Step-by-step explanation:
If D is the midpoint of side BC of triangle ABC and AD is bisected at point E and BE produced cuts AC at point X, how can you prove that BE:EX = 3:1?
Let's take point Y on seg AC such that DY | | BX.
As D is a midpoint of BC, by converse of midpoint theorem, XY=YC.
Applying midpoint theorem in triangle CDY, BX=2DY.
As E is a midpoint of AD & EX | | DY,
AX=XY.
Applying midpoint theorem in triangle DAY, EX= DY/2
BE/EX = BX-EX / EX
= 2DY - DY/2 / DY/2
= 3DY / 2 * 2/YD
= 3DY/DY
= 3:1.