D is the midpoint of side BC of triangle ABC and e is the midpoint of the median ad prove that area of triangle b e d is equal to 1 by 4 into area of triangle ABC
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In triangle BED and ABD
angleD=angle D( common)
DE/AD=BD/BC
or DE/2DE=BD/2DC ( D and E are midpoints)
by SAS similarity triangle BED and ABD
ar(BED)/ar(ABC)= DE/AD square
"" , , ,,,,,. =DE/2DE square
then,=1/4
ar(BED)=1/4arABC proved
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