D is the point of side Bc such that AD=AC.Show that AD<AB
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question improper plz finish your question
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AD = AC ( given)
So, < d = < c
In triangle ABD
Exterior angle d > angle b ( as exterior angle is greater than its interior opposite angle.)
But < d = < c
→<c greater than <b
→AB > AC ( as, side opposite to greater angle is greater in a triangle)
But, AC = AD
So, AB > AD
Hence Proved.
So, < d = < c
In triangle ABD
Exterior angle d > angle b ( as exterior angle is greater than its interior opposite angle.)
But < d = < c
→<c greater than <b
→AB > AC ( as, side opposite to greater angle is greater in a triangle)
But, AC = AD
So, AB > AD
Hence Proved.
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