D is the point on the side BC of a triangle ABC such that |_ADC=|_BAC . Show that CA2=CB . CD
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Answer:
CA2=CB
Step-by-step explanation:
IN ΔABC AND ΔADC
∠C = ∠C (COMMON)
∠BAC =∠ADC
∴ ΔABC ≈ ΔADC (AA CRITERIA)
∴AC/DC = BC/AC (CPST)
∴CA²=CB*CD
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