Question

D is the point on the side of BC of triangle ABC such that AD bisects angle BAC then​

Answer 1

Step-by-step explanation:

We are given that D is a point on the side BC of a triangle ABC such that AD bisects angle BAC. And we have to show that BA > BD. Now, as we know that the exterior angle of a triangle is greater than the interior opposite angles of the triangle. Hence proved that BA > BD.

Answer 2

Answer:

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Step-by-step explanation:

Given-

AD is the angular bisector of a triangle ABC.

AD meets BC at D.

To find out-

which of the given options is true.

Solution-

AD is the bisector of ∠BAC.

∴∠BAD=∠CAD.

Again , in ΔACD,∠ADCis the external angle .

We know that the external angle of a triangle is greater than each intrenal opposite angle of the same triangle.

∴∠ADB=∠DAC+DCA.

=∠BAD+∠DCA(∵∠DAC=∠BAD)

i.e∠ADC>∠BAD.

∴BA>BD.

So option B is true.

Option A is true only when the triangle is equlateral or isosceles.

Option C is false since Option B is true.

option D is false since

∠ADC>∠BADor ∠CAD

∴CD≯CA\

Ans- Option B.