Question

d lemon flavoured candy?
7. It is given that in a group of 3 students, the probability of 2 students not having the
same birthday is 0.992. What is the probability that the 2 students have the same
birthday?
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Answer 1

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008

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Answer 2

$\huge\mathcal{\fcolorbox{aqua}{azure} {\red{ question}}}$

It is given that in a group of 3 student , the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

$\huge\mathcal{\fcolorbox{aqua}{azure} {\red{ Answer}}}$

Probability that two students are not having same birthday = 0.992

Probability that two students are not having same birthday

= -1 Probability that two students are having same birthday

P (not same birthday) = 1-P (Same birthday)0.992= 1-P (same birthday)

P (same birthday) = 1-0.992

P ( same birthday) = 0.008

So probability that 2 students will have the same birthday is 0.008