d light ray enters a liquid at an angle of incidence as
And gets refracted on liquid at angle of refraction 30°.
Calculate the refrective index of the liquid.
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Answer:
Given : i=45
0
r=30
0
(μ
air
)
To find : μ
water
Solution: From snell's law
μ
1
sini=μ
2
sinr
μ
air
sin45
0
=μ
w
sin30
0
2
1
=
2
μ
w
μ
w
2
Now let us take that for angle of incidence α the angle between reflected ray and refracted ray be 90
0
then
α+r+90
0
=180
0
/90
0
(since i = angle of reflection from laws of reflection)
Hence r=90−α
Now from snell's law
μ
1
sinα=μ
2
sinr
1sinα=
2
sin(90−α)
tanα=
2
α=tan
−1
2
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