Question

(d) None of these
The sides of a triangle have length 112 cm, 78 cm and 50 cm. Find the area​

Answer 1

Answer:

Step-by-step explanation:

the formula for it is 1/2 base x height

Answer 2

Answer:

Let

$a = 50cm</p><p> \\ b = 78cm</p><p> \\ c = 112$

$S = \frac{a + b + c}{2}$

$S = \frac{50+78+112}{2}$

$S = \frac{240}{2} = 120$

$Area = \sqrt{s(s - a)(s -b)(s - c)}$

$\sqrt{120(120 - 50)(120 - 78)(120 - 112)}$

$=2822400$

$= 1680 cm {}^{2}$

$Longest \: side = 120cm$

$corresponding \: to \: this \: side \: as \: the \\ </p><p>base \: the \: altitude \: will \: be \: smallest.$

$area = \frac{1}{2} \times base \times altitude$

$= 1680 \times \frac{1}{2} \times 112 \times altitude$

$=altitude = 1680 \times \frac{2}{211}   \\ </p><p>= 30cm$

hope it helps you