А D O С B 19. In the given figure, straight lines AB and CD intersect at O. If ZAOC + ZBOD = 130° then ZAOD = ? (a) 65° (b) 115° (c) 110° (d) 125
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From the figure we know that ∠AOC and∠AOD from a linear pair
It can also be written as
∠AOC+∠AOD=180
o
By substituting the values
50
o
+∠AOD=180
o
∠AOD=180
o
−50
o
∠AOD=130
o
According to the figure we know that ∠AOD and ∠BOC are vertically opposite angles
So we get
∠AOD=∠BOC=180
o
According to the figure we know that ∠AOC and ∠BOD are vertically opposite angles
So we get
∠AOC+∠BOD=50
o
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