Question

d(p,r)=7,d(p,q)=10,d(q,r)=3 identify the point p,q,r are collinear?​

Answer 1

Step-by-step explanation:

Given that PQR are three collinear points and

PQ=2.5. Let us now find the distance of PR

Recall Distance Formula is =$$ \sqrt { { \left( { x}_{ 2 }{ { x }_{ 1 } } \right) }^{ 2}+{ \left( { y }_{ 2 }{ { y }_{ 1 } } \right) }^{ 2 } } \\$$

Distance PR=

(113)

2

)+(104)

2

=

100

=10

Let us now consider S is the midpoint of PR,

then we have the co-ordinates of S as

2

11+3

,

2

10+4

=(7,7).

∴ it is clear that Q is the

midpoint of PS as we have know PQ=2.5 units.

Thus, to get the co-ordinates of Q take

midpoint of PS which is

2

3+7

,

2

4+7

=(5,11/2).