Question

D product of two numbers is 2662 if the LCM of these numbers is 242 find the HCF

Answer 1

Given: The product of the two numbers is 2662. & the LCM of these two given numbers is 242.

Need to find: The HCF?

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❍ Let's say, that the HCF of the two numbers be x.

$\longrightarrow\sf\quad HCF \times LCM = Product_{\:(Numbers)}$

$\longrightarrow\sf\quad x \times 242 = 2662$

$\longrightarrow\sf\quad 242x = 2662$

$\longrightarrow\sf\quad x = \cancel\dfrac{2662}{242}$

$\longrightarrow\quad\underline{\boxed{\pmb{\frak{\red{x = 11}}}}}\;\bigstar$

$\therefore{\underline{\textsf{Hence, the HCF of two numbers is \textbf{11}.}}}$

$\rule{230px}{.2ex}$

• V e r i f i c a t i o n :

• Now, Let's verify the answer by substituting the value of x as 11.

⠀

$\dashrightarrow\sf\quad HCF \times LCM = Product_{\:(Numbers)}$

$\longrightarrow\sf\quad x \times 242 = 2662$

$\dashrightarrow\sf\quad 11 \times 242 = 2662$

$\dashrightarrow\quad\underline{\boxed{\pmb{\frak{2662=2662}}}}$

$\qquad\qquad\qquad\therefore{\underline{\pmb{\mathcal{HENCE\; VERIFIED!}}}}$

Answer 2

Answer:

Question :-

• The product of two numbers is 2662.If the LCM of these numbers is 242.Find the HCF.

Answer :-

• The HCF of given two numbers is 11.

Given :-

• The product of two numbers is 2662.If the LCM of these numbers is 242.

To find :-

• The HCF of given two numbers.

Solution :-

• First let start the conversation of your question.

In the question given that the the product of two numbers is 2662.If the LCM of these numbers is 242.We need to find the HCF if given two numbers.

• So,

• We know the formula that is ,

• Let consider the HCF of given two numbers be m.

• Then,

• LCM×HCF=Total product.

• Here we know the values.

• That is,

• 242×m=2662

• $242m = 2662$

• $m = \frac{2662}{242} = 11$

$\mathcal\red{Therefore ,}$

• The HCF of given two numbers is 11.

Verifying Answer :-

• Total given product =HCF×LCM(Value of HCF=11)
• Product=11×242
• Product =2662

• Hence verified.

Hope it helps u mate .

Thank you .