Social Sciences, asked by pandayritu787, 7 months ago


d) Raghav placed a 37-foot ladder against a wall. If the base of the ladder is 12 feet
from the base of the wall, how high will the ladder reach up the wall?​

Answers

Answered by mayankarora21
4

Answer

Acd. to pythagorous theorem

(Base)^2 +(Height)^2= (Hypotenuse)^2

(12×12) +( 37 ×37) = (Hypotenuse)^2

144+1369= (Hypotenuse)^2

1513 =(Hypotenuse)^2

38.9=Hypotenuse

^2 means square

Answered by shouryavardhan84
14

Answer:

Consider a triangle ABC, with B as tha right angle.

According to the question,

The length of ladder= 37m (This is the hypotenuese - AC)

&

Distance between the building and ladder = 12m ( BC )

We need to find AB i.e. the height at which the ladder would reach.

Using Pythagoras Theorem,

We can say that

AB^2 + BC^2 = AC^2

Therefore-:

AB^2= AC^2 - BC^2

AB^2= 37^2 - 12^2

AB^2= 1369 - 144

AB^2= 1225

Ans = 35m

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