Question

d (sin 5x. cos3x)
dx​

Answer 1

Answer:

There you go,

$\frac{d (sin 5x. cos3x)}{dx}\\\\= sin 5x \frac{d(cos3x)}{dx} + cos 3x \frac{d(sin5x)}{dx}\\\\=-3 sin 5x sin3x + 5cos3xcos5x$