(d) sin2A + cos4 A-cos2A - sin4A
Answers
Answered by
0
Answer:
cos 4 A - Cos2A
= (cos2A)2 - (cosA)2
= (1- sin2A)2 - cos2A
= 1 + sin4A - 2sin2A -( 1- sin2A)
=1+ sin4A - 2 sin2A -1 + sin2A
=sin4A - sin2A
since LHS = RHS
hence proved.
Step-by-step explanation:
Answered by
0
Answer:
cos
4
A−cos
2
A=sin
4
A−sin
2
A
LHS.
=cos
2
A(1−cos
2
A)
=cos
2
Asin
2
A[∵sin
2
A+cos
2
A=1]
RHS
=sin
2
A(1−sin
2
A)
=sin
2
Acos
2
A[∵sin
2
A+cos
2
A=1]
=cos
2
Asin
2
A
LHS=RHS
Hope it helps!
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