Question

d
$\frac{d}{?}$
​

Answer 1

Step-by-step explanation:

$\sf \frac {d( {e}^{x + klogx)}}{dx} \\ \\ \sf {e}^{x+klogx}\frac{d( x + klogx )}{dx} \\ \\ \sf {e}^{x + klogx}( \frac{ d (x) }{dx} + k\frac {d(logx)}{dx}) \\ \\ \sf {e}^{x+klogx}( 1 + \frac{k}{x} \\ \\ \sf {\boxed {\red{ \frac {d (x)}{dx} = 1 }}} \\ \\ \sf {\boxed {\red{\frac { d (logx)}{dx} = \frac {1}{x} }}}\\ \\ \sf {\boxed{\red{\frac {d({e}^{x}}{dx} = {e}^{x} }}}$

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