Question

d) The area of contact of the brick with powdered lime when it is placed vertically is 0.02 m²
calculate the pressure exerted by the brick of weight 30 N on the lime powder.​

Answer 1

The pressure exerted by the weight of the brick on the lime powder is 1500 Pa

Explanation:

Given:

The area of contact of brick = 0.02 m²

Force due to weight of the brick = 30 N

To find out:

The pressure exerted by the brick on the lime powder

Solution:

We know that

Pressure = Force/Area of contact

or, P=\frac{F}{A}P=AF

Here,

F = 30 N

A = 0.02 m²

Thus,

P=\frac{30}{0.02}P=0.0230 N/m²

\implies P=1500⟹P=1500 Pa

Hope this answer is helpful.

Know More:

Q: A brick has a weight of 15 N. If the pressure it produces is 0.5 N/cm(2) what is the area in contact with the ground?

Click Here: https://brainly.in/question/22227432

Answer 2

Understanding the question:

⋆ This question says that we have to find out the pressure that is exerted by the brick that have a weight of 30 Newton's on the lime power where the area of contact of the brick with powdered lime when it is placed vertically is 0.02 metres sq.

Provided that:

• Weight = 30 Newton

• Area of contact of brick… = 0.02m

To calculate:

• Pressure

Solution:

• Pressure = 1500 Pascal

Knowledge required:

➟ The force acting on an object perpendicular to the surface is known as thrust.

➟ The thrust on unit area is known as pressure. Henceforth,

• ${\small{\underline{\boxed{\sf{Pressure \: = \dfrac{Thrust}{Area}}}}}}$

It can be also written as

${\small{\underline{\boxed{\sf{Pressure \: = \dfrac{Force}{Area}}}}}}$

➟ SI unit of pressure is N/m² but in honour of scientist Blaise Pascal it's SI is Pascal that is denoted by Pa.

Required solution:

~ Using the formula to find pressure let's find the pressure exerted by the brick on the lime powder. Let's do it!

$:\implies \sf Pressure \: = \dfrac{Force}{Area} \\ \\ :\implies \sf Pressure \: = \dfrac{30}{0.02} \\ \\ :\implies \sf Pressure \: = \cancel{\dfrac{30}{0.02}} \qquad (Cancelling) \\ \\ :\implies \sf Pressure \: = \cancel{\dfrac{15}{0.01}} \qquad (Cancelling) \\ \\ :\implies \sf Pressure \: = \dfrac{15 \times 100}{1} \\ \\ :\implies \sf Pressure \: = \dfrac{1500}{1} \\ \\ :\implies \sf Pressure \: = 1500 \: Pascal$

Solution: 1500 Pa is the force exerted by the brick on the lime powder.