Question

D. The compound intrest on 230,000 at
74. per annum is 74347 - The Period
(in years) is​

Answer 1

Principle=74347

R=74%, T=?, C.I.= 230,000

By compound interest formula,

C.I.= P×(1+r/100)power(t)

230,000= 74347(1+74/100)power(t)

230,000/74347= (174/100)power(t)

3.09360162481= (174/100)power(t)

3.09360162481/1.74= t

1.7= t

So, n= 1 year 7 months

Answer 2

Answer:

Step-by-step explanation:

P=230000

R=74 % p.a.

Let time =x

$CI=P(1+\frac{R}{100} )^T\\\\74347=230000(1+\frac{74}{100} )^T\\\\(\frac{174}{100}) ^T=\frac{74347}{230000} \\\\\log_{\frac{87}{50} }[(\frac{87}{50} )^T]=\log_{\frac{87}{50} } (\frac{74347}{230000})\\\\T\approx -2.03894??$

Pls check ur question. There is a mistake. Also, such a question is likely not going to appear in 8th standard syllabus.