Question

d the current flowing through the resistance R1 of the circuit shown in figure if the resistance are equal to R1 = 10 , R2 =20 , and R3 = 30 , and the potential of points 1, 2 and 3 are equal to 10V, 1  2  6V and 3  5V . 1 R1 R2 R2 2 O 3 (A) 0.1 A (B) 0.2 A (C) 0.3 A (D) 0.4 A

Answer 1

Answer:

i hope you will understand friend

Answer 2

We can distribute the current as shown in the figure.

From the figure, we conclude,

$\varphi_1-\varphi_2 = iR_1 + i_1R_2\\\\and, \ \varphi_1 - \varphi_3 = iR_1 +(i-i_1)R_3$

On simplifying the above two equations, we will obtain,

$i=\dfrac{R_3(\varphi_1 - \varphi_2) + R_2(\varphi_1 -\varphi_3) }{R_1R_2+R_2R_3+R_3R_1 }$

Putting the values you will get i = 0.2 A