Question

(D) The distance of the plane 2x-3y +6z +7 = 0 from the point ( 2, -3, - 1) is (B) 3 (A) 2 (D) 7 6 .JC)​

Answer 1

Answer:

(D) The distance of the plane 2x-3y +6z +7 = 0 from the point ( 2, -3, - 1) is (B) 3 (A) 2 (D) 7 6 .JC)

Step-by-step explanation:

jthe distance of the plane 2x-3y +6z +7 = 0 from the point ( 2, -3, - 1) is (b) 3 (a) 2 (d) 7 6 .jc)

h

jthe distance of the plane 2x-3y +6z +7 = 0 from the point ( 2, -3, - 1) is (b) 3 (a) 2 (d) 7 6 .jc)

I don't know

Answer 2

Answer:

answer is 7

solution just add the given point (2, -3, -1) as X, Y, Z

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