Question

D. The force constant of a wire is k and that of another wire is 2k. When both the wires are
stretched through same distance, then the work done
[MH CET 2000]
(a) W2 = 2W?
(b) W, = 2W,
(c) = W
(d) W, -0.5W,​

Answer 1

Answer:

W∝K

K2=2K1

W2=2W1

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Answer 2

Explanation:

work required=change of energy

=1/2kx²

so answer is (a

)