Question

(D)
The oxidation number of Ni in [Ni(CO)4) is
(A) 0
(B)2
(C) 3.
(D)4​

Answer 1

Answer:

0

Explanation:

Sum of oxidation numbers of individual atoms = Total charge on compound

=> Oxidation number of Ni + 4 ( Oxidation number of CO ) = 0

=> x + 4(0) = 0

=> x = 0

Oxidation number of Ni = 0