Question

d) The pH of a 0.0001 m NaOH ​

Answer 1

Answer:

For NaOH, normality is equal to molarity.

[OH

−

]=[NaOH]=0.0001N=0.0001M

pOH=−log[OH

−

]=−log0.0001=4

pH=14−pOH=14−4=10.

Explanation:

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