Question

D. The relation between K and K for the
reaction A (g)+B (g) = 2C (g) +D
(g) is
a. Kc = Ykp b. Kp = Kc2
c. Kc = v d. Kp/Kc = 1​

Answer 1

Answer:

we know,

Kp = Kc (RT)^delta ng

here,

delta ng = 3(no. of moles of gases on the product side) - 2(no. of moles of gases on the reactants side) = 1

therefore,

Kp = Kc (RT)^1 = KcRT

Answer 2

The relation between $K_p$ and $K_c$ for the reaction is $K_p=\frac{K_c}{RT}$

Explanation:

$A(g)+B(g)\rightarrow 2C(g)+D(g)$

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

$K_p$ = equilibrium constant in terms of partial pressure

$K_c$ = equilibrium constant in terms of concentration

R = Gas constant

T = temperature

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=3-2=-1$

Putting values in above equation, we get:

$K_p=K_c\times (R\times T)^{-1}\\\\K_p=\frac{K_c}{RT}$

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