Math, asked by tauqueerahmad10, 10 months ago

d the smallest number of 6 digits which when divided by 25, 35,
is remainder in each case,
ur bags can hold 30 kg, 54 kg, 66 kg and 72 kg of sugar. Find the
ich can be put into exact number of small bags. Also find the nu
ich total amount of sugar is kept.
the greatest number of 4 digits which when divided by 4, 12, 1
and 22 as remainders respectively.
the smallest number of 6 digits which on being diminished by
15, 20, 30, 40, 50 and 60.
bells ring at an interval of 20, 15, 25 and 30 minutes. All the
2 noon At what time will they again ring together?​

Answers

Answered by rajivrtp
0

Step-by-step explanation:

All your questions are based on LCM andHCF

please solve yourself

Answered by sunitafunde45
0

100000 is the 6dight smallest no.

30kg. 1bag

54kg 2bag

66kg 3bag

72kg 4bag

first,, 100000÷30 =3333.33........... (1)

second, 100000÷54=1851.85..........(2)

third, 100000÷66=1515.15..............(3)

fourth, 100000÷72=1388.88..........(4)

now, second condition

greatest no. of4 dight=9999

divided by 4,12,1

remander=22

smallest no. of 6 right witch starting

15,20,30,40,50,60

bell rings= 20,15,25,30

2noons again ring=?

now,9999÷4=2499.75

9999÷12=833.25

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