Question

d the sum of all 3-digit numbers,which leave the remainder 1,when divided by SIX ?

Answer 1

(1÷6)=3x   you get 0.166666=3x(divide by 3) hence =0.0555555

Answer 2

Answer:

82 500

Step-by-step explanation:

103, 109, 115, ..., 997

997=103+(n-1)*6  (A.P.)

n=150

S=150/2*(103+997)

S=82 500