d) The sum of four consecutive odd numbers is 80. Find the numbers
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Answered by
0
Answer:
let the four numbers are
x, x+2,x+4 and x+6
a.q. x+x+2+x+4+x+6= 80
= 4x+ 12=80
=4x= 80-12
= 4x = 68
= x= 68/4
=x= 17
so the 4 numbers are 17,19,21 and 23
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Answered by
0
Answer:
1st no.=x+1
2nd no.=x+3
3rd no.=x+5
4th no.=x+7
x+1+x+3+x+5+x+7=80
4x+16=80
4x=80-16
4x=64
x=64/4
x=16
x+1=16+1=17
x+3=16+3=19
x+5=16+5=21
x+7=16+7=23
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