Question

D.U.
A and B together can do a piece of work in 30 days. A having worked for 16 days,
B finishes the remaining work alone in 44 days. In how many days shall B finish the
whole work alone ?
(C.B.I. 1997)​

Answer 1

Answer:

Hello,

Please find the method below.

Let A's 1 day's work = x and B's 1 day's work = y.

Both A's and B's 1 day work=1/30

i.e (A's 1 day + B's 1 day)=1/30

i.e x + y = 1/30........eq1

now,

A having worked for 16 days, B finishes the remaining work alone in 44 days

i.e work done by A in 16 days = 16x

Remaining work done B= 1 - 16x

but Remaining work is done by B in 44days i.e 44y

i.e. 44y=1-16x

i.e 16x+44y=1........eq2

solving eq1 & eq2,

we get,x = 1/60 and y = 1/60

B's 1 day's work = 1/60.

Hence, B alone shall finish the whole work in 60 days