Math, asked by sandas7399, 1 year ago

(d) undefined
Pick the odd man out.
(a) ACFJ
(b) CEHL
(c) PRUY
(d) SUXZ

Answers

Answered by Anonymous
28

Answer : (a) SUXZ

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EXPLAINATION :

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As we can see in the options, there are some codes are given :

(a) ACFJ

(b) CEHL

(c) PRUY

(d) SUXZ

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On taking option (a) :

ACFJ

First Letter : A

  • A - ( B ) - C ( 1 letter is removed)

  • C - ( D & E ) - F ( 2 letters )

  • F - ( G, H & I ) - J = ACFJ

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On taking option (b) :

CEHL

First Letter : C

  • C - ( D ) - E ( 1 letter is removed)

  • E - ( F & G ) - H ( 2 letters )

  • H - ( I, J & K ) - L = CEHL

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On taking option (c) :

PRUY

First Letter : P

  • P - ( Q ) - R ( 1 letter is removed)

  • R - ( S & T ) - U ( 2 letters)

  • U - ( V, W & X ) - Y = PRUY

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On taking option (d) :

SUXZ

First Letter : S

  • S - ( T ) - U ( 1 letter is removed)

  • U - ( V & W ) - X ( 2 letters)

  • X - ( Y ) - Z = SUXZ

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As we can see that it in the sequence of of the given codes : after first letter, one letter is removed, after that two letters are removed and at last three letters are removed. but in the option d in the last only one letter is removed. So, the odd one will be option (d).

Answered by deepraj26101
0

Answer:

A

Step-by-step explanation:

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