Question

(d) x^{3}+4x^{2}-4x-16~by(x-2)​

Answer 1

Step-by-step explanation:

$\huge \frac{{x}^{3} + 4x ^{2} - 4x - 16}{x - 2}$

$\huge \frac{{x}^{3} + 4x ^{2} - 4x - 8}{x }$

$\huge\frac{4 {x}^{7 } - 4x - 8 } {x}$

Answer 2

Step-by-step explanation:

x

3

+4x

2

−4x−16

\huge \frac{{x}^{3} + 4x ^{2} - 4x - 8}{x }

x

x

3

+4x

2

−4x−8

\huge\frac{4 {x}^{7 } - 4x - 8 } {x}

x

4x

7

−4x−8