Question

(d) x^{3}+4x^{2}-4x-16~by(x-2)
please answer me fast ...
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Answer 1

Answer:

The remainder is 0 and hence (x-2) is a factor of x^{3}+4x^{2}-4x-16

Step-by-step explanation:

x^{3}+4x^{2}-4x-16 is to be divided by(x-2)

.: We need to subsitute the value, x = 2 , in the eq.

= x^{3}+4x^{2}-4x-16

= 2^{3}+4 * 2^{2} -4 * 2 -  16

= 8 + 4 * 4 - 8 - 16

= 0 + 16 - 16

= 0

.: The remainder is 0 and hence (x-2) is a factor of x^{3}+4x^{2}-4x-16

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