Physics, asked by yash81830, 8 months ago

d(x^4+2sinx + 3cosx)/dx​

Answers

Answered by Santhosh2925
0

Answer:

4x^3+2cosx-3sinx

Explanation:

d(x^4+2sinx+3cosx)/dx

d/dx(x^4)+d/dx(2sinx)+d/dx(3cosx)

4x^3+2cosx-3sinx. (d/dx(sinx)=cosx)

(d/dx(cosx)= --sinx)

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