d(x^4+2sinx + 3cosx)/dx
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Answer:
4x^3+2cosx-3sinx
Explanation:
d(x^4+2sinx+3cosx)/dx
d/dx(x^4)+d/dx(2sinx)+d/dx(3cosx)
4x^3+2cosx-3sinx. (d/dx(sinx)=cosx)
(d/dx(cosx)= --sinx)
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