Question

D={x:x belongs to rational no and 3x -2 =0} is this set Singleton or not plz ans​

Answer 1

Answer:

Option A is right

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cm

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cm

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm 2

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm 2

Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm 2 ∴ Perimeter remains the same but area changes.