(D). zero
. A particle of mass m moving in the x-direction with speed 2v is hit by another
particle of mass 2m moving in the y-direction with speed v. if the collision is
perfectly inelastic, the percentage loss in the energy during the collision is close to
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Answer:
m
1
V
1
+m
2
V
2
=(m
1
+m
2
)
V
→
V
→
=[
m
1
+m
2
m
1
V
1
→
+m
1
V
2
→
]
=
m+2m
(m)(2V)
i
∧
+(2m)(v)
j
∧
=
3m
(2mv)[
i
∧
+
j
∧
]
=
3
2
V[
i
∧
+
j
∧
]
=
V
f
→
∴∣
V
f
→
∣=
3
2
V
2
KE
f
=
2
1
(3m)(
9
4
)V
2
(2)
KE
i
=
2
1
(m)(2V
2
)+
2
1
(2m)(V
2
)
KE
i
KE
i
+KE
f
=56%
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