Question

d1=d ,d2=d4 ,D1=D, D2=4D ,W1=?​

Answer 1

Answer:

91

Step-by-step explanation:

Four fair dices rolled simultaneously.

Total number of outcomes=6×6×6×6

Suppose, the out come of the last one does not appear in the first three.

The number of such outcomes possible=6×5

3

(∵D

1

can show any of 6 numbers and first three can show any of the remaining 5 numbers)

Hence, probability that D 4

does not show a number shown by any of D 1 ,D 2orD3

= 6 4

6×5 3

So, the required probability

=1− 6 46×5 3

= 216

91

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