Question

d1and d2 (d2greater than d1) be diameters of 2 conc. circles and c length of a chord of a circle which is tangent of the other circle proove that d2²=c²+d1² awswer quickly get marked as brainlest answer

Answer 1

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Step-by-step explanation:

Answer: Given :  d1, d2 (d2>d1) be the diameters of two concentric circles and C be the lengths of a chord of a circle which is tangent to the other circle

To prove : d2= d1 2 + C2

 

Now

,

OQ = d2/2 , OR = d1/2 and PQ=c

Since PQ istangent to the circle  

therefore OR is perpendicular to PQ

=> QR = PQ/2 = c/2

 

Using pythagorus theorm in triangle OQR

OQ2 = OR2 + QR2

=> (d2 /2)2 = (d1/2)2 + (c/2)2

=>1/4 (d2)2 = 1/4 (d1)2 +(c)2

=> d22 = d12 +c2

Hence Proved