Question

(D²+1)x+ (D+1)y= 1, D²x - Dy = t-1​

Answer 1

Answer
On solving the given equation
x =0
y =0
Step-by-step explanation:
(D^2 +1)x + (D+1)y =1. (1)\\
D^2x -Dy =t-1. (2)\\
On differentiating above equations We get,
2Dx +y = 0 (3)\\
2Dx -y = 0 (4)\\
Add equ 3 and 4 we get
4Dx =0
x = 0
On substituting the value of x in equ 4 we get
y= 0