Question

(D2 + 2D + 2) y = e–2x + cos2x​

Answer 1

Answer:

Differential Equations

D = 2, –2, 1, –1 are the roots. Hence its solution is y = c. 1 e2x + c. 2 e–2x + c. 3 ex + c. 4 ... Its A.E. is D3 – 2D2 – 4D + 8 = 0. ∴. D2 ... Example 4: Solve (D2 + 4) (D2 + 1) y = cos 2x + sin x.

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