Math, asked by tongamer787, 3 months ago

(d² + d+2)y = e sin x ​

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Answered by Sarah0909
24

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(D+1)(D+3)y=e −x sinx+xe 3x C.F. = C 1 e −x +C 2 e −3x For P.I. , we getD 2 +4D+3e −x sinx+xe 3x e −x D(D+2)sinx +e 3x (D+4)(D+6)x e

(D+1)(D+3)y=e −x sinx+xe 3x C.F. = C 1 e −x +C 2 e −3x For P.I. , we getD 2 +4D+3e −x sinx+xe 3x e −x D(D+2)sinx +e 3x (D+4)(D+6)x e −x

(D+1)(D+3)y=e −x sinx+xe 3x C.F. = C 1 e −x +C 2 e −3x For P.I. , we getD 2 +4D+3e −x sinx+xe 3x e −x D(D+2)sinx +e 3x (D+4)(D+6)x e −x

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(D+1)(D+3)y=e −x sinx+xe 3x C.F. = C 1 e −x +C 2 e −3x For P.I. , we getD 2 +4D+3e −x sinx+xe 3x e −x D(D+2)sinx +e 3x (D+4)(D+6)x e −x D(D 2 −4)(D−2)sinx

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