(d²+d)y=(x²+2x+4) please find answer for me
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I hope this is helpful for you
Step-by-step explanation:
We have to solve (D2−4D+1)y=x2
The characteristic equation is p2−4p+1=0
⇒p=24±16−4=24±23=2±3
Thus Complementary function C.F.=Ae(2+3)x+Be(2−3)x
Particular integral P.I.=D2−4D+11(x2)
=[1−(4D−D2)]−1(x2)
=[1+(4D−D2)+(4D−D2)2+...](x2)
=[1+4D+15D2+...](x2)
∴P.I.=x
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