(D³ - 6 D²D' + 11 DD'² + 2 D'³) z=e^5x+6y
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The answer is slightly different but the method is same.
(D^3-6 D^2+11D-6)y=e^-2x
Let f(D)= D^3 -6 D^2+11D--6
The A E is f(m) =0
m^3--6m^2+11m —6 (2)
(m-1) is a factor
( m-2)ia factor
(m-3) is afactor
The Roots of( 2) are 1 2 and 3
CF = yc =c1 e^x + c2 e^2x +c3 e-^3x
yp=PI = 1/ (D-1) (D-2)( D-3) e^-3x
Here f(2)=0 let phi (D) =D-1 then Ph(i2)= 2-1 =/ 0 AND K=2
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